Definition: Null space. Let be linear. The null space of or the kernel of (denoted ).
We know that as
Proposition: , linear
is a linear subspace of .
Proof: Pick
TBA
Proposition: is linear then if and only if is one-one.
Proof: Pick such that , as is a linear map
So,
Therefore,
Hence, is one to one.
Other side: Note,
Pick
Then,
Since is one to one,
So essentially, we have a lot of vectors in the domain that map to zero
But we also have a lot of vectors that map to non-zero vectors, which gives the transform its non-triviality
Say some is linear is also linear, and a subspace
What follows is that is you have transform is linear, then is a subspace
In conclusion, the vectors in all map to , and the rest of the vectors span
Example: ,
Definition: Rank-nullity. Rank is the dimension of , nullity is the dimension of
Let be a linear map. Then,
Proof: Since is a subspace, let be a basis of .
Pick is linearly independent.
as is a basis, ,
Pick and complete it to a basis of
Remains to show
Proof of rank nullity: Note that is a linear subspace of the codomain . Thus, there exists such that , which is a basis of .
Now, we shall show that is linearly independent. Suppose . This implies that . We can apply the linear property such that . Therefore,
Since is a subspace, say, is a basis of .
Claim: is a basis of . We know this because the union of two linearly independent sets is linearly independent from our homework.
Pick . Either , or
This implies that , given .
This implies that
which implies that
Which implies that So, is a basis of . P.